(2a^2+a+3)/(a-1)

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Solution for (2a^2+a+3)/(a-1) equation: 


D( a )

a-1 = 0

a-1 = 0

a-1 = 0

a-1 = 0 // + 1

a = 1

a in (-oo:1) U (1:+oo)

(2*a^2+a+3)/(a-1) = 0

2*a^2+a+3 = 0

2*a^2+a+3 = 0

DELTA = 1^2-(2*3*4)

DELTA = -23

DELTA < 0

1 = 0

1/(a-1) = 0

a belongs to the empty set

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